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Solution Of Ncert __hot__ May 2026

It sounds like you're asking for (likely for Mathematics or Science, for classes 6–12). Since you didn't specify the subject, class, chapter, or exercise , I’ll provide a general structured answer format that follows NCERT solution style — along with a fully worked example.

Substitute ( x = 14 - y ) into the second equation: [ (14 - y) - y = 4 ] [ 14 - 2y = 4 ] [ -2y = 4 - 14 ] [ -2y = -10 ] [ y = 5 ] solution of ncert

Substitute ( y = 5 ) back into ( x = 14 - y ): [ x = 14 - 5 = 9 ] It sounds like you're asking for (likely for

If you reply with the exact details (e.g., Class 10 Maths, Chapter 3, Exercise 3.3, Question 2 ), I can give you the precise solution. Chapter 3: Pair of Linear Equations in Two Variables Exercise 3.3, Question 1 (i) Solve the following pair of linear equations by the substitution method: ( x + y = 14 ) ( x - y = 4 ) Solution: Step 1: From the first equation, express ( x ) in terms of ( y ): [ x = 14 - y ] Chapter 3: Pair of Linear Equations in Two

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It sounds like you're asking for (likely for Mathematics or Science, for classes 6–12). Since you didn't specify the subject, class, chapter, or exercise , I’ll provide a general structured answer format that follows NCERT solution style — along with a fully worked example.

Substitute ( x = 14 - y ) into the second equation: [ (14 - y) - y = 4 ] [ 14 - 2y = 4 ] [ -2y = 4 - 14 ] [ -2y = -10 ] [ y = 5 ]

Substitute ( y = 5 ) back into ( x = 14 - y ): [ x = 14 - 5 = 9 ]

If you reply with the exact details (e.g., Class 10 Maths, Chapter 3, Exercise 3.3, Question 2 ), I can give you the precise solution. Chapter 3: Pair of Linear Equations in Two Variables Exercise 3.3, Question 1 (i) Solve the following pair of linear equations by the substitution method: ( x + y = 14 ) ( x - y = 4 ) Solution: Step 1: From the first equation, express ( x ) in terms of ( y ): [ x = 14 - y ]