I_fault = (Transformer FLA) / (%Z/100) Where FLA = (kVA × 1000) / (V_secondary × √3 for 3‑phase)
For a secondary fault:
Cable impedance reduces AFC to ≈ 9.2 kA at the panelboard.
Long cables reduce AFC. Subtract voltage drop impedance from available current. ⚠️ Manual calculations are error‑prone for complex systems. Use a dedicated calculator or software (e.g., EasyPower, SKM, ETAP, or web tools like Copper Bussmann FC2). Example Scenario Transformer: 500 kVA, 480V secondary, 5.75% Z FLA secondary = 500,000 / (480 × 1.732) ≈ 601 A I_fault (transformer terminals) = 601 / (0.0575) ≈ 10,452 A (10.45 kA)
Get from utility: Fault MVA or Short-circuit current at transformer primary .
Available Fault Current Calculator May 2026
I_fault = (Transformer FLA) / (%Z/100) Where FLA = (kVA × 1000) / (V_secondary × √3 for 3‑phase)
For a secondary fault:
Cable impedance reduces AFC to ≈ 9.2 kA at the panelboard. available fault current calculator
Long cables reduce AFC. Subtract voltage drop impedance from available current. ⚠️ Manual calculations are error‑prone for complex systems. Use a dedicated calculator or software (e.g., EasyPower, SKM, ETAP, or web tools like Copper Bussmann FC2). Example Scenario Transformer: 500 kVA, 480V secondary, 5.75% Z FLA secondary = 500,000 / (480 × 1.732) ≈ 601 A I_fault (transformer terminals) = 601 / (0.0575) ≈ 10,452 A (10.45 kA) I_fault = (Transformer FLA) / (%Z/100) Where FLA
Get from utility: Fault MVA or Short-circuit current at transformer primary . 5.75% Z FLA secondary = 500